A) \[PC{{l}_{3}}\]
B) \[PC{{l}_{5}}\]
C) \[SoC{{l}_{2}}\] in presence of pyridine
D) dry \[HCl\] in the presence of anhydrous \[ZnC{{l}_{2}}\]
Correct Answer: C
Solution :
The best method for the conversion of an alcohol into an alkyi chloride is by treating the alcohol with \[SOC{{l}_{2}}\] in the presence of pyridine. \[ROH+SOC{{l}_{2}}\xrightarrow{{}}\text{ }RCl+HCl+S{{O}_{2}}\] The other products being gases escape leaving behind pure alkyi halide.
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