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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2009

  • question_answer
    A body of mass x kg is moving with a velocity of \[100\text{ }m{{s}^{-1}}\]. Its de-Broglie wavelength is\[6.62\times {{10}^{-35}}m\]. Hence, x is \[(h=6.62\times {{10}^{-34}}Js)\]

    A)  \[0.1kg\]             

    B)  \[0.25kg\]

    C)  \[0.15kg\]         

    D)  \[0.2kg\]

    Correct Answer: A

    Solution :

    \[\lambda =\frac{h}{mv}\] \[=\frac{6.62\times {{10}^{-34}}}{6.62\times {{10}^{-35}}\times 100}\] \[=0.1kg\]


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