A) nucleophilic attack, transfer of \[{{H}^{-}}\] and transfer of \[{{H}^{+}}\]
B) transfer of \[{{H}^{-}}\], transfer of \[{{H}^{+}}\] and nucleophilic attack
C) transfer if \[{{H}^{+}}\] nucleophilic attack and transfer of \[{{H}^{-}}\]
D) electrophilic attack by \[O{{H}^{-}}\], transfer of \[{{H}^{+}}\] and transfer of \[{{H}^{-}}\]
Correct Answer: A
Solution :
The Cannizaro reaction is as \[HCHO+HCHO\xrightarrow{KOH(con.)}\underset{methyl\,alcohol}{\mathop{C{{H}_{3}}OH}}\,\] \[\underset{+acetic\,acid}{\mathop{+HCOO{{K}^{+}}}}\,\] The mechanism of Cannizaro reaction is as Step 1st: Attack of nucleophile \[O{{H}^{-}}\] to the carbonyl carbonYou need to login to perform this action.
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