CET Karnataka Medical CET - Karnataka Medical Solved Paper-2010

  • question_answer
    The empirical formula of a non-electrolyte is\[C{{H}_{2}}O\]. A solution containing \[6g\]of the compound exerts the same osmotic pressure as that of \[0.05M\]glucose solution at the same temperature. The molecular formula of the compound is

    A)  \[{{C}_{2}}{{H}_{4}}{{O}_{2}}\]  

    B)  \[{{C}_{3}}{{H}_{6}}{{O}_{3}}\]

    C)  \[{{C}_{5}}{{H}_{10}}{{O}_{5}}\]     

    D)  \[{{C}_{4}}{{H}_{8}}{{O}_{4}}\]

    Correct Answer: D

    Solution :

    Solutions having same osmotic pressure, at a given temperature, have same concentration Concentration of compound = concentration of glucose \[\frac{6}{M\times 1}=0.05\] \[M=\frac{6}{0.05}=120\] Empirical formula mass \[(C{{H}_{2}}O)=12+2+16\] \[=30\] \[n=\frac{miolecular\,mass}{empirifal\,formula\,mass}\] \[=\frac{120}{30}=4\] Hence, molecular formula \[={{(C{{H}_{2}}O)}_{4}}={{C}_{4}}{{H}_{8}}{{O}_{4}}\]


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