2. Solved Papers
  3. CET Karnataka Medical

CET Karnataka Medical CET - Karnataka Medical Solved Paper-2010

  • question_answer
    Cell A and cell B are adjacent plant cells. In cell A, \[{{\psi }_{p}}\] = - 20 bars and \[{{\psi }_{p}}\] = 8 bars. In cell B, \[{{\psi }_{S}}\] = -12 bars and \[{{\psi }_{p}}\] = 2 bars. Then,

    A)  water moves from cell B to cell A

    B)  equal amount of water is simultaneously exchanged between cell A and cell B

    C)  water moves from cell A to cell B

    D)  there is no movement of water between cell A and cell B

    Correct Answer: A

    Solution :

    Movement of water between cell takes place along the water potential gradient, water moves from a cell having higher water potential to a cell having lower water potential. Cell B has higher water potential (-12 bars + 2 bars = -10 bars), whereas cell A has lower water potential (-20 bars +8 bars = -12 bars). Hence, water will move from cell B to cell A.


You need to login to perform this action.
You will be redirected in 3 sec spinner