A) \[C{{H}_{3}}Br\]
B) \[C{{H}_{3}}CON{{H}_{2}}\]
C) \[C{{H}_{3}}N{{H}_{2}}\]
D) \[C{{H}_{3}}B{{r}_{3}}\]
Correct Answer: C
Solution :
\[C{{H}_{3}}C{{H}_{2}}Br\xrightarrow[\Delta ]{aq.\,KOH}\underset{(A)}{\mathop{C{{H}_{3}}C{{H}_{2}}OH}}\,\xrightarrow[\Delta ]{KMn{{O}_{4}}/{{H}^{+}}}\]\[\underset{(B)}{\mathop{\underset{acetic\,acid}{\mathop{C{{H}_{3}}COOH}}\,}}\,\xrightarrow{N{{H}_{3}}}C{{H}_{3}}COON{{H}_{4}}\xrightarrow{\Delta }\underset{(C)}{\mathop{\underset{acetamide}{\mathop{C{{H}_{3}}CON{{H}_{2}}}}\,}}\,\] \[\xrightarrow{B{{r}_{2}}/alkali}\underset{(D)}{\mathop{\underset{\text{methyl}\,\text{amine}}{\mathop{C{{H}_{3}}N{{H}_{2}}}}\,}}\,\]You need to login to perform this action.
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