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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2010

  • question_answer
    The dimensions of resistance are same as those of ...... where h is the Plancks constant, e is the charge.

    A)  \[\frac{{{h}^{2}}}{{{e}^{2}}}\]

    B)  \[\frac{{{h}^{2}}}{e}\]

    C)  \[\frac{h}{{{e}^{2}}}\]

    D)  \[\frac{h}{e}\]

    Correct Answer: C

    Solution :

    Resistance, \[R=\frac{V}{i}=\frac{W}{qi}=\frac{[M{{L}^{2}}{{T}^{-2}}]}{[{{A}^{2}}T]}\] \[R=[M{{L}^{2}}{{T}^{-3}}{{A}^{-2}}]\] For\[\left[ \frac{h}{{{e}^{2}}} \right]=\frac{[M{{L}^{2}}{{T}^{-1}}]}{{{[AT]}^{2}}}=[M{{L}^{2}}{{T}^{-3}}{{A}^{-2}}]\]


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