CET Karnataka Medical CET - Karnataka Medical Solved Paper-2010

  • question_answer
    The temperature of a gas contained in a closed vessel of constant volume increases by \[1{}^\circ C\]when the pressure of the gas is increased by 1 %. The initial temperature of the gas is

    A)  100 K

    B)  \[273{}^\circ \text{ }C\]

    C)  \[100{}^\circ \text{ }C~\]

    D)  \[200\text{ }K\]

    Correct Answer: A

    Solution :

    According to Gay Lussacs law \[p\propto T\] \[\therefore \] \[\frac{dp}{p}\times 100=\frac{dT}{T}\times 100\] \[1=\frac{1}{T}\times 100\]\[\Rightarrow \]\[T=100K\]


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