A) 1.5 C
B) 6 C
C) C
D) 3 C
Correct Answer: A
Solution :
The equivalent diagram of the given circuit is \[{{C}_{1}},{{C}_{2}}\]and \[{{C}_{3}}\] are in parallel \[\therefore \] \[{{C}_{123}}={{C}_{1}}+{{C}_{2}}+{{C}_{3}}\] \[=C+C+C=3C\] Similarly, \[{{C}_{456}}=3C\]\[{{C}_{123}}\]and \[{{C}_{456}}\]are in series \[\therefore \]\[{{C}_{eq}}=\frac{(3C)(3C)}{3C+3C}=1.5C\]You need to login to perform this action.
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