A) \[N\] and \[0\]
B) \[Na\] and \[Mg\]
C) \[Mg\] and \[Al\]
D) \[Be\] and \[B\]
Correct Answer: B
Solution :
Na belongs to IA group and Mg belongs to IIA group. On moving form left to right in a period, first ionization energy increases, thus, IE of \[Mg\] is greater than the IE of Na. IE order \[Mg>Na\]You need to login to perform this action.
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