A) the point D will be at a potential of 60 V
B) the point D will be at a potential of 20 V
C) currents in the paths AD, DB and DC are in the ratio of 1 : 2 : 3
D) currents in the paths AB, DB and DC are in the ratio of 3 : 2 : 1
Correct Answer: C
Solution :
Applying Kirchhoffs law at point D, we get \[{{I}_{1}}={{I}_{2}}+{{I}_{3}}\] \[\frac{{{V}_{A}}-{{V}_{D}}}{10}=\frac{{{V}_{D}}-0}{20}+\frac{{{V}_{D}}-{{V}_{C}}}{30}\] or \[70-{{V}_{D}}=\frac{{{V}_{D}}}{2}+\frac{{{V}_{D}}-10}{3}\] \[\Rightarrow \]\[{{V}_{D}}=40V\]\[\Rightarrow \]\[{{i}_{1}}=\frac{70-40}{10}=3A\] \[{{i}_{2}}=\frac{40-0}{20}=2A\]and\[{{i}_{3}}=\frac{40-10}{30}=1A\]You need to login to perform this action.
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