A) \[\frac{15}{\sqrt{2}}A\]
B) \[8A\]
C) 18 A
D) 10 A
Correct Answer: A
Solution :
Resistance, \[R=\frac{100}{10}=10\Omega \] Inductive reactance,\[{{X}_{L}}=2\pi fL\] \[\frac{100}{8}=2\pi \times 50\times L\] \[\Rightarrow \] \[L=\frac{1}{8\pi }H\] \[X{{}_{L}}=2\pi f\,L=2\pi \times 40\times \frac{1}{8\pi }=10\Omega \] Impedance of the circuit is \[Z=\sqrt{{{R}^{2}}+X_{L}^{2}}\] \[=\sqrt{{{(10)}^{2}}+{{(10)}^{2}}}=10\sqrt{2}\Omega \] Current in the circuit is\[i=\frac{V}{2}=\frac{150}{10\sqrt{2}}=\frac{15}{\sqrt{2}}A\]You need to login to perform this action.
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