A) \[0.0355g\]
B) \[0.071g\]
C) \[6.023\times {{10}^{21}}\]Molecules
D) \[0.02mol\]
Correct Answer: A
Solution :
Ideal gas equation is \[pV=nRT\] When V and T are same, \[P\alpha N\] Thus, when number of moles, ie, n is least, it will exert least pressure. [a] \[n=\frac{wt}{35.5}=\frac{0.0355}{35.5}=1\times {{10}^{-3}}\] [b] \[n=\frac{0.071}{35.5}=2\times {{10}^{-3}}mol\] [c] \[n=\frac{number\,of\,molecules}{{{N}_{A}}}\] \[=\frac{6.023\times {{10}^{21}}}{6.023\times {{10}^{23}}}=0.01mol\] [d] \[n=0.02mol\] Thus, \[0.0355g\]chlorine will exert the least pressure.
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