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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2010

  • question_answer
    In Kjeldahls method, ammonia from \[5g\]of food neutralizes \[30c{{m}^{3}}\]of \[0.1N\]acid. The percentage of nitrogen in the food is

    A)  \[0.84\]           

    B)  \[8.4\]

    C)  \[16.8\]            

    D)  \[1.68\]

    Correct Answer: A

    Solution :

    From Kjeldahls method, percentage of nitrogen \[=\frac{1.4\times N\times V}{w}=\frac{1.4\times 0.1\times 30}{5}\] \[=0.84%\]


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