A) an aldehyde
B) a primary alcohol
C) a secondary alcohol
D) a ketone
Correct Answer: B
Solution :
Because the difference in mass between \[-C{{H}_{2}}OH\] group and \[-COOH\]group is 14, thus the compound which undergoes oxidation is a primary alcohol. (\[-C{{H}_{2}}OH\] is the functional group of primary alcohols.) \[\underset{primary\,alcohol}{\mathop{\underset{(R+31)}{\mathop{RC{{H}_{2}}OH}}\,}}\,\xrightarrow{[O]}\underset{acid}{\mathop{\underset{(R+45)}{\mathop{RCOOH}}\,}}\,\]
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