A) 1.25
B) 0.25
C) 5
D) 10
Correct Answer: B
Solution :
For minimum wavelength, \[\lambda \propto {{n}^{2}}\] \[\therefore \] \[\frac{{{\lambda }_{Lyman}}}{{{\lambda }_{Balmer}}}={{\left( \frac{1}{2} \right)}^{2}}\] \[\frac{{{\lambda }_{L}}}{{{\lambda }_{B}}}=\frac{1}{4}=0.25\]You need to login to perform this action.
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