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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2011

  • question_answer
    Wavelength of given light waves in air and in a medium are \[\text{6000}\overset{\text{o}}{\mathop{\text{A}}}\,\] and \[\text{4000}\overset{\text{o}}{\mathop{\text{A}}}\,\] respectively. The critical angle is

    A)  \[{{\tan }^{-1}}\left( \frac{2}{3} \right)\]

    B)  \[{{\tan }^{-1}}\left( \frac{3}{2} \right)\]

    C)  \[si{{n}^{-1}}\left( \frac{2}{3} \right)\]

    D)  \[si{{n}^{-1}}\left( \frac{3}{2} \right)\]

    Correct Answer: C

    Solution :

    \[\frac{1}{\sin C}=\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}\] \[\frac{1}{\sin C}=\frac{6000}{3000}\] \[\frac{1}{\sin C}=\frac{6}{3}=\frac{3}{2}\] \[\sin C=\frac{2}{3}\] \[C={{\sin }^{-1}}\left( \frac{2}{3} \right)\]


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