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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2011

  • question_answer
    Two thin lenses have a combined power of +9D. When they are separated by a distance of 20 cm, their equivalent power become \[+\frac{27}{5}D.\]Their individual powers (in dioptre) are

    A)  1, 8              

    B)  2, 7

    C)  3, 6               

    D)  4, 5

    Correct Answer: C

    Solution :

    Given, \[{{p}_{1}}+{{p}_{2}}=9\] \[p={{p}_{1}}+{{p}_{2}}-d{{p}_{1}}{{p}_{2}}\] \[\frac{27}{5}=9-\frac{20}{100}\times {{p}_{1}}{{p}_{2}}\] Hence, the above equation is correct for \[{{p}_{1}}=3\]and \[{{p}_{2}}=6.\]


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