A) \[{{i}_{1}}=1.5A\], \[{{i}_{2}}=0.5\text{ }A\]
B) \[{{i}_{1}}=0.5A\], \[{{i}_{2}}=1.5\text{ }A\]
C) \[{{i}_{1}}=\text{ }1\text{ }A\], \[{{i}_{2}}=\text{ }3\text{ }A\]
D) \[{{i}_{1}}=\text{ }3\text{ }A\], \[{{i}_{2}}=\text{ }1\text{ }A\]
Correct Answer: B
Solution :
Resistance\[R=\frac{12\times 4}{12+4}+2=\frac{48}{16}+2=5\Omega \] Electric current\[I=\frac{E}{R+r}=\frac{12}{6}=2A\] \[{{I}_{1}}+{{I}_{2}}=2A\] \[I\propto \frac{1}{R}\] \[\therefore \] \[{{I}_{2}}=1.5A,{{I}_{1}}=0.5A\]
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