A) 5 m
B) 2.5 m
C) 10 m
D) 12.5 m
Correct Answer: A
Solution :
Given, \[m=5\,kg\] and KE = 490 J By the law of conservation of energy \[\frac{1}{2}m{{u}^{2}}=\frac{1}{2}m{{v}^{2}}+mgh\] \[490=245+5\times 9.8\times h\] \[h=\frac{490-245}{5\times 9.8}\] \[h=\frac{245}{49}\] \[=5m\]You need to login to perform this action.
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