A) 13 units
B) 16 units
C) 20 units
D) 24 unit
Correct Answer: C
Solution :
Intensity, \[I\propto \frac{1}{{{\lambda }^{4}}}\] \[\therefore \] \[\frac{{{I}_{2}}}{{{I}_{1}}}={{\left( \frac{{{\lambda }_{1}}}{{{\lambda }_{2}}} \right)}^{4}}\] \[\frac{{{I}_{2}}}{{{I}_{1}}}={{\left( \frac{500}{400} \right)}^{4}}\cong 2.5\] \[{{I}_{2}}=2.5{{I}_{1}}=2.5\times 8\] \[{{I}_{2}}=20.5\approx 20\]units
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