CET Karnataka Medical CET - Karnataka Medical Solved Paper-2011

  • question_answer
    The amount of heat evolved when \[500c{{m}^{3}}\]of \[0.1M\text{ }HCl\]is mixed with \[200c{{m}^{3}}\]of \[0.2M\] \[NaOH\]is

    A)  \[2.292\text{ }kJ\]

    B)  \[1.292\text{ }kJ\]

    C)  \[22.9\text{ }kJ\]

    D)  \[0.292\text{ }kJ\]

    Correct Answer: A

    Solution :

    No. of equivalents of \[NaOH\] reacting \[=\frac{40}{1000}\] \[1eq=57.3\] \[\frac{40}{1000}eq=\frac{57.3\times 40}{1000}=2.292kJ\]


You need to login to perform this action.
You will be redirected in 3 sec spinner