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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2011

  • question_answer
    The enthalpy of vaporization of benzene is \[+35.3\text{ }kJ/mol\]at its boiling point,\[{{80}^{o}}C\]. The entropy change in the transition of vapour to liquid at its boiling point is

    A)  \[-100\]          

    B)  \[+100\]

    C)  \[+342\]

    D)  \[-342\]

    Correct Answer: A

    Solution :

    \[\Delta H=+35.3kJ/mol\] \[\Delta S=\frac{\Delta H}{T}=\frac{+35.3}{35.3}=0.1kJ/mol/K\] \[\Delta S=0.1\times {{10}^{3}}=1000J/mol/K\] Entropy change in the transition of vapour to liquid is negative, \[\Delta S=-100\].


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