A) \[2{{K}_{1}}=K_{2}^{2}\]
B) \[K_{1}^{2}=\frac{1}{{{K}_{2}}}\]
C) \[K_{2}^{2}=\frac{1}{{{K}_{1}}}\]
D) \[{{K}_{2}}=\frac{2}{K_{1}^{2}}\]
Correct Answer: B
Solution :
\[S{{O}_{2}}(g)+\frac{1}{2}{{O}_{2}}(g)S{{O}_{3}}(g)\] ?..(i) \[{{K}_{1}}\] Equation (i) is reversed and multiplied by 2 \[2S{{O}_{3}}(g)2S{{O}_{2}}(g)+{{O}_{2}}(g)\] (i) \[\frac{1}{K_{1}^{2}}\] \[2S{{O}_{3}}(g)2S{{O}_{2}}(g0+{{O}_{2}}(g)\] (ii) \[{{K}_{2}}\] \[\therefore \] \[{{K}_{2}}=\frac{1}{K_{1}^{2}}\] \[K_{1}^{2}=\frac{1}{{{K}_{2}}}\]
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