A) \[4\]
B) \[7\]
C) \[5\]
D) \[6\]
Correct Answer: C
Solution :
\[F{{e}^{2+}}-[Ar]3{{d}^{6}}\] It has 4 unpaired electrons \[\therefore \] \[\mu =\sqrt{n(n+2)}\] \[=\sqrt{4(4+2)}\] \[=\sqrt{24}\] \[\mu =4.89BM\approx 5BM\]You need to login to perform this action.
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