A) \[4.8\]
B) \[1.2\]
C) \[7.7\]
D) \[9.6\]
Correct Answer: A
Solution :
: Nuclear radius \[R={{R}_{0}}{{A}^{1/3}}\] where \[{{R}_{0}}\]is a constant and A is the mass number \[{{R}_{Cu}}=(1.2\times {{10}^{-15}}m)\,{{(64)}^{1/3}}\] \[=(1.2\times {{10}^{-15}}m)\,{{({{4}^{3}})}^{1/3}}\] \[=4.8\times {{10}^{-15}}m=4.8fm\] ( \[\because \] \[1fm={{10}^{-15}}m\])You need to login to perform this action.
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