CET Karnataka Medical CET - Karnataka Medical Solved Paper-2012

  • question_answer
    For a transistor, \[\beta =100\]. The value of a is

    A)  \[1.01\]   

    B)  \[0.99\]

    C)  \[100\]   

    D)  \[0.01\]

    Correct Answer: B

    Solution :

    : Given:   \[\beta =100\] As   \[\alpha =\frac{\beta }{1+\beta }=\frac{100}{1+100}=\frac{100}{101}=0.99\]


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