A) \[10\]
B) \[5\]
C) \[20\]
D) \[4\]
Correct Answer: A
Solution :
In the given figure \[3\mu F\] and \[3\mu F\] are in parallel Their equivalent capacitance is \[6\mu F\]. The equivalent circuit is as shown in the figure. The equivalent capacitance between A and B is \[\frac{1}{C}=\frac{1}{6}+\frac{1}{3}+\frac{1}{6}+\frac{1}{3}=\frac{1+2+1+2}{6}=\frac{6}{6}\] or \[C=1\mu F\] Charge in the circuit, \[Q=CV=(1\mu F)(60V)=60\mu C\] The potential difference across \[6\mu F\] capacitor is \[=\frac{60\mu C}{6\mu F}=10V\]You need to login to perform this action.
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