A) \[8\]
B) \[4\]
C) \[40\]
D) \[80\]
Correct Answer: C
Solution :
: Intensity level, \[L=10\log \left( \frac{I}{{{I}_{0}}} \right)dB\] where \[{{I}_{0}}\]= threshold intensity \[={{10}^{-12}}W{{m}^{-2}}\] Here, \[I={{10}^{-8}}W{{m}^{-2}}\] \[\therefore \] \[L=10\log \left( \frac{{{10}^{-8}}}{{{10}^{-12}}} \right)dB\] \[=10\log ({{10}^{4}})dB=40dB\]You need to login to perform this action.
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