A) \[T{{i}^{3+}}\]
B) \[{{V}^{3+}}\]
C) \[C{{r}^{3+}}\]
D) \[F{{e}^{3+}}\]
Correct Answer: A
Solution :
: Magnetic moment \[(\mu )=\sqrt{n(n+2)}\] B.M. where n = number of unpaired electrons.No. of unpaired | Magnetic moment (B.M.) | |
\[T{{i}^{3+}}:3{{d}^{1}}\,4{{s}^{0}}\] | \[1\] | \[1.73\] |
\[{{V}^{3+}}:3{{d}^{2}}\,4{{s}^{0}}\] | \[2\] | \[2.83\] |
\[C{{r}^{3+}}:3{{d}^{3}}\,4{{s}^{0}}\] | \[3\] | \[3.87\] |
\[F{{e}^{3+}}:3{{d}^{5}}\,4{{s}^{0}}\] | \[5\] | \[5.92\] |
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