A) \[91\]
B) \[111\]
C) \[55.5\]
D) \[75.5\]
Correct Answer: B
Solution :
Let the compound be\[MC{{l}_{2}}\]. Bivalent mass of a metal ion \[\approx \frac{Atomic\,mass}{Total\,positive\,valency}\] \[20=\frac{Atomic\,mass\,of\,the\,metal\,ion}{2}\] \[\Rightarrow \]Atomic mass of the metal \[=2\times 20=40\] \[\therefore \]Molecular mass of anhydrous chloride \[(MC{{l}_{2}})\] \[=40+(2\times 35.5)\] \[=40+71=111\]
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