A) \[80mL\]
B) \[40mL\]
C) \[60mL\]
D) \[30mL\]
Correct Answer: D
Solution :
: \[C{{H}_{4}}+{{O}_{2}}\xrightarrow{{}}C{{O}_{2}}+{{H}_{2}}O\] \[22400mL\]of methane requires \[22400mL\]of oxygen for burning. \[\therefore \] \[20mL\]of methane will require \[=20mL\]of oxygen. This means that \[20mL\] of methane will burn completely using \[20mL\] of oxygen. \[\therefore \]Volume of the gas left will be of oxygen only \[=(50-20)=30mL\]
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