A) \[6.02\times {{10}^{23}}\]
B) \[6.02\times {{10}^{25}}\]
C) \[6.02\times {{10}^{24}}\]
D) \[6.02\times 18\times {{10}^{23}}\]
Correct Answer: C
Solution :
: 1 molecule of \[{{H}_{2}}O\] contains \[(2+8)\]=10 electrons Mass of \[18mL\]of water = volume \[\times \] density \[=18\times 1=18g\]. Molecular mass of \[{{H}_{2}}O\] (18 g) contains \[6.023\times {{10}^{23}}\]molecules 1 molecule of\[{{H}_{2}}O\] contains 10 electrons. \[\therefore \] \[6.023\times {{10}^{23}}\] molecules will have \[=6.023\times {{10}^{23}}\times 10=6.023\times {{10}^{24}}\]electrons
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