A) methyl cyclobutane
B) cyclopentane
C) cyclobutane
D) methyl cyclopentane.
Correct Answer: A
Solution :
: \[{{H}_{2}}\underset{Br}{\mathop{\underset{|}{\mathop{C}}\,}}\,-C{{H}_{2}}-C{{H}_{2}}-\underset{Br}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-C{{H}_{3}}\xrightarrow[-2NaBr]{2Na/\Delta }\]
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