A) \[0\]
B) \[1\]
C) \[3\]
D) \[4\]
Correct Answer: D
Solution :
: According to vant Hoffs equation, no. of option isomers = 2 (when the molecule has no symmetry). Where, n = no. of chiral carbon atoms. \[C{{H}_{3}}-\overset{*}{\mathop{C}}\,HBr-\overset{*}{\mathop{C}}\,HBr-COOH\] No. of chiral carbons \[=2\] \[\therefore \]No. of optical isomers are \[={{2}^{n}}={{2}^{2}}=4\]You need to login to perform this action.
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