CET Karnataka Medical CET - Karnataka Medical Solved Paper-2013

  • question_answer
    A gun fires a small bullet with kinetic energy K.  Then kinetic energy of the gun while recoiling is 

    A)  K                 

    B)  more than K      

    C)  less than K       

    D)  \[\sqrt{K}\]

    Correct Answer: C

    Solution :

    : Recoil velocity of the gun, \[\upsilon =-\frac{mu}{M}\]  ?..(i) - ve sign shows that recoil of the gun Where m is the mass of the bullet, M is the mass of the gun and u is the velocity of bullet. \[\therefore \] Kinetic energy of the bullet, \[K=\frac{1}{2}m{{u}^{2}}\] Kinetic energy of the gun while recoiling, \[K=\frac{1}{2}M{{u}^{2}}\] \[\therefore \] \[\frac{K}{K}=\frac{M}{m}\left( \frac{{{\upsilon }^{2}}}{{{u}^{2}}} \right)=\frac{M}{m}{{\left( \frac{m}{M} \right)}^{2}}=\frac{m}{M}\] (Using (i)) As \[m<<M\]\[\therefore \] \[K<K\]


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