CET Karnataka Medical CET - Karnataka Medical Solved Paper-2013

  • question_answer
    Excess of \[PC{{l}_{5}}\] reacts with concentrated \[{{H}_{2}}S{{O}_{4}}\] giving

    A)  chlorosulphuric acid

    B)  sulphurous acid

    C)  sulphuryl chloride

    D)  thionyl chloride.

    Correct Answer: C

    Solution :

    : \[\underset{Sulphuric\,acid}{\mathop{HO-S{{O}_{2}}-OH}}\,\xrightarrow[-POC{{l}_{3}}-HCl]{PC{{l}_{5}}}\] \[\underset{\begin{smallmatrix}  Chlorosulphonic \\  acid \end{smallmatrix}}{\mathop{HO-S{{O}_{2}}-Cl}}\,\xrightarrow[-POC{{l}_{3}}-HCl]{PC{{l}_{5}}}\underset{\begin{smallmatrix}  Sulphuryl \\  chloride \end{smallmatrix}}{\mathop{S{{O}_{2}}C{{l}_{2}}}}\,\]


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