A) \[{{\beta }_{1}}<{{\beta }_{2}}\]
B) \[{{\beta }_{1}}={{\beta }_{2}}\]
C) \[{{\beta }_{1}}>{{\beta }_{2}}\]
D) \[{{\beta }_{1}}\ge {{\beta }_{2}}\]
Correct Answer: A
Solution :
: Fringe width, \[\beta =\frac{\lambda D}{d}\] \[\therefore \] \[B\propto \lambda \] \[\therefore \] \[\frac{{{\beta }_{1}}}{{{\beta }_{2}}}=\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}\] \[{{\lambda }_{1}}\] can produce photoelectric effect and \[{{\lambda }_{2}}\] cannot produce photoelectric effect. \[\Rightarrow \] \[{{\lambda }_{1}}<{{\lambda }_{2}}\] \[\therefore \] \[{{\beta }_{1}}<{{\beta }_{2}}\]You need to login to perform this action.
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