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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2014

  • question_answer
    For the equilibrium : \[CaC{{O}_{3(s)}}Ca{{O}_{(s)}}+C{{O}_{2(g)}};\,{{K}_{p}}=1.64atm\] at \[1000K\] \[50g\]of \[CaC{{O}_{3}}\]in a 10 litre closed vessel is heated to 1000 K. Percentage of \[CaC{{O}_{3}}\] that remains unreacted at equilibrium is (Given:\[R=0.082L\text{ }atm\text{ }{{K}^{-1}}\text{ }mo{{l}^{-1}}\])

    A)    

    B)    

    C)    

    D)  \[20\]

    Correct Answer: C

    Solution :

    : For the reaction, \[CaC{{O}_{3(s)}}Ca{{O}_{(s)}}+C{{O}_{2(g)}}\] \[{{K}_{c}}=[C{{O}_{2}}]\] or \[{{K}_{p}}={{p}_{C{{O}_{2}}}}\] No. of moles of \[CaC{{O}_{3(s)}}=\frac{Mass}{Mol.\,mass}\]                   \[=\frac{50}{100}=0.5\] Applying ideal gas equation,     \[PV=nRT\]     \[1.64\times 10=n\times 0.082\times 1000\] No. of moles of \[C{{O}_{2}},\,n=0.2\] No. of moles of unreacted \[CaC{{O}_{3}}=0.5-0.2\]      \[=0.3\] % of unreacted \[CaC{{O}_{3}}=\frac{0.3}{0.5}\times 100=60%\]


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