A) \[\frac{4}{17}A\]
B) \[4A\]
C) \[1A\]
D) \[\frac{4}{3}A\]
Correct Answer: C
Solution :
Resistors \[2\Omega \], and \[6\Omega \], are connected in parallel. Their equivalent resistance is \[\frac{1}{{{R}_{P}}}=\frac{1}{2}+\frac{1}{6}=\frac{4}{6}=\frac{2}{3}\] \[{{R}_{P}}=\frac{2}{3}\Omega =1.5\Omega \] Current flowing through the battery is \[I=\frac{\varepsilon }{{{R}_{P}}+r}=\frac{2V}{1.5\Omega +0.5\Omega }=1A\]You need to login to perform this action.
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