A) \[C{{l}_{2}},ClF,U{{F}_{6}},Cl{{F}_{3}}\]
B) \[C{{l}_{2}},Cl{{F}_{3}},U{{F}_{6}},ClF\]
C) \[{{O}_{2}},O{{F}_{2}},{{U}_{2}}{{O}_{3}},{{O}_{2}}{{F}_{2}}\]
D) \[{{O}_{2}},{{O}_{2}}{{F}_{2}},{{U}_{2}}{{O}_{3}},O{{F}_{2}}\]
Correct Answer: B
Solution :
: \[Mn{{O}_{2}}+4HCl\xrightarrow{\Delta }\underset{(A)}{\mathop{C{{l}_{2(g)}}}}\,+MnC{{l}_{2}}+2{{H}_{2}}O\] \[\underset{(A)}{\mathop{C{{l}_{2}}_{(g)}}}\,+3{{F}_{2(excess)}}\xrightarrow{573K}\underset{(B)}{\mathop{2Cl{{F}_{3(g)}}}}\,\] \[\underset{(A)}{\mathop{3Cl{{F}_{3(l)}}}}\,+{{U}_{(s)}}\xrightarrow{\Delta }\underset{(C)}{\mathop{U{{F}_{6(g)}}}}\,+\underset{(D)}{\mathop{3Cl{{F}_{3(g)}}}}\,\]You need to login to perform this action.
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