A) \[8314\text{ }J\text{ }mo{{l}^{-1}}\]
B) \[1.202kJ\text{ }mo{{l}^{-1}}\]
C) \[12.02\text{ }J\text{ }mo{{l}^{-1}}\]
D) \[83.14\text{ }kJ\text{ }mo{{l}^{-1}}\]
E) None of the Above
Correct Answer: E
Solution :
It should Be 1n k vs 1 /T Plot of in k vs 1/T gives Slope \[=-\frac{{{E}_{a}}}{R}\] \[\therefore \] \[-1\times {{10}^{4}}=-\frac{{{E}_{a}}}{8.314}\] \[{{E}_{a}}=8.314\times {{10}^{4}}J\,mo{{l}^{-1}}=83.14\times {{10}^{3}}J\,mo{{l}^{-1}}\]or \[{{E}_{a}}=83.14kJ\,mo{{l}^{-1}}\]
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