A) \[0.5\Omega \]
B) \[\frac{5}{9.95}\Omega \]
C) \[0.05\Omega \]
D) \[\frac{9.95}{5}\Omega \]
Correct Answer: B
Solution :
: Here, Resistance of galvanometer, \[G=100\Omega \] Full scale deflection current, \[{{I}_{g}}=5mA\] \[=5\times {{10}^{-3}}A\] To convert the galvanometer into an ammeter of range 1 A, a shunt resistance of value S is connected in parallel with it such that, \[(I-{{I}_{g}})={{I}_{g}}G\] \[S=\frac{{{I}_{g}}G}{I-{{I}_{g}}}=\frac{5\times {{10}^{-3}}\times 100}{1-5\times {{10}^{-3}}}=\frac{5\times {{10}^{-1}}}{1-0.005}\] \[=\frac{0.5}{0.995}=\frac{5}{9.95}\Omega \]You need to login to perform this action.
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