A) \[2T\]
B) \[2\times {{10}^{-8}}T\]
C) \[\frac{1}{2}T\]
D) \[1\times {{10}^{-8}}T\]
Correct Answer: B
Solution :
: The magnitude of magnetic field is \[B=\frac{E}{c}=\frac{6V{{m}^{-1}}}{3\times {{10}^{8}}m\,{{s}^{-1T}}}=2\times 10h-8\]You need to login to perform this action.
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