A) \[8\]
B) \[0.5\]
C) \[10\]
D) \[2\]
Correct Answer: D
Solution :
: Let \[{{V}_{0}}\] be the potential difference between the plates of an air filled parallel plate capacitor. When a dielectric slab is introduced between its plates, its potential difference will become \[V=\frac{{{V}_{0}}}{K}\]c where K is the dielectric constant of the slab. \[\therefore \] \[K=\frac{{{V}_{0}}}{V}\] Here, \[{{V}_{0}}=4V,V=2V\] \[\therefore \] \[K=\frac{4V}{2V}=2\]You need to login to perform this action.
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