A) \[{{P}_{4}}{{O}_{10}}\]
B) \[Ba{{O}_{2}}\]
C) \[M{{g}_{3}}{{N}_{2}}\]
D) \[Ca{{C}_{2}}\]
Correct Answer: B
Solution :
: \[{{P}_{4}}{{O}_{10}}+6{{H}_{2}}O\to \underset{Orthophosphoric\,acid}{\mathop{4{{H}_{3}}P{{O}_{4}}}}\,\] \[M{{g}_{3}}{{N}_{2}}+6{{H}_{2}}O\to 3Mg{{(OH)}_{2}}+2N{{H}_{3}}\] \[Ca{{C}_{2}}+2{{H}_{2}}O\to Ca{{(OH)}_{2}}+{{C}_{2}}{{H}_{5}}\]
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