A) \[36,500g\text{ }mo{{l}^{-1}}\]
B) \[34,500g\text{ }mo{{l}^{-1}}\]
C) \[35,400g\text{ }mo{{l}^{-1}}\]
D) \[35,600g\text{ }mo{{l}^{-1}}\]
Correct Answer: D
Solution :
: \[L-\text{amino acid}\,\xrightarrow[{{0}^{o}}C]{NaN{{O}_{2}}+HCl}{{N}_{2}}\uparrow \] 1 mole of L-amino acid \[\to \] 1 mole of \[{{N}_{2}}\] \[=22400c{{m}^{3}}\]of \[{{N}_{2}}\] at STP \[448c{{m}^{3}}\] of \[{{N}_{2}}\equiv 1.78g\] of L-amino acid \[22,400\text{ }c{{m}^{3}}\]of \[{{N}_{2}}\equiv xg\]of L-amino acid Sample of protein has 0.25% amino acid.Amino acid | Protein |
\[0.25\] | \[100\] |
\[89\] | \[y\] |
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