A) \[5\]
B) \[10\]
C) \[4\]
D) \[6\]
Correct Answer: A
Solution :
: \[FeS{{O}_{4}}.{{(N{{H}_{4}})}_{2}}S{{O}_{4}}.6{{H}_{2}}O\xrightarrow{Excess\,{{H}_{2}}O}\] \[F{{e}^{2+}}+2NH_{4}^{+}+2SO_{4}^{2-}+6{{H}_{2}}O\]
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