A) \[20min\]
B) \[15min\]
C) \[3hr\]
D) \[30min\]
Correct Answer: A
Solution :
: For a first order reaction: \[k=\frac{2.303}{t}\log \frac{{{[A]}_{0}}}{[A]}=\frac{2.303}{60}\log \frac{100}{12.5}=0.0346{{\min }^{-1}}\]Now \[{{t}_{1/2}}=\frac{0.693}{k}=\frac{0.693}{0.0346}=20\min \]You need to login to perform this action.
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