A) \[0.34V\]
B) \[2.1V\]
C) \[0.5V\]
D) \[0.21V\]
Correct Answer: D
Solution :
: The emf developed between the tips of the wings is \[\varepsilon ={{B}_{V}}{{l}_{V}}\] Here, \[{{B}_{V}}=1.75\times {{10}^{-5}}T,\,l=40m\] \[v=1080km/hr=1080\times \frac{5}{18}m\,{{s}^{-1}}\] \[=300\,m\,{{s}^{-1}}\] \[\therefore \] \[\varepsilon =(1.75\times {{10}^{-5}}T)(40m)(300\,m\,{{s}^{-1}})\] \[=0.21V\]You need to login to perform this action.
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